PHYS 10111 Lecture 4: Example Problems

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28 Mar 2019
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At point 2 at time t2 , the particle has a zero velocity in y-direction v (t2) = 7. 6 i + ( 6. 1 9. 8 t2) j = 7. 6 i + 0 j. At the highest point, the particle is 11m (1. 9 + 9. 1) above the ground. At point 3 at time t3, r (t3) = 7. 6 t3 i + ( 6. 1 t3 4. 9 t3. 2 ) j = 7. 6 t3 i - 9. 1 j. 2 6. 1 t3 - 9. 1 = 0, a = 4. 95, b = -6. 1, c = -9. 1 t3 = [-b ( b2 4ac)1/2]/2a. R = vox trt = 7. 6 * 3 = 22. 8 m. At t = t3 = 2. 12s, dr(t)/dt = v (t3) = 7. 6 i + ( 6. 1 9. 8 t3) j v(2. 12) = 7. 6 i + ( 6. 1 9. 8 *2. 12) j = 7. 6 i 14. 7 j.