MAT 114 Lecture Notes - Lecture 7: Solution Set, Size Function
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3 1 4 y t 5 e 15. Note both sides of an inequality can be multiplied by a negative constant of inequality is reversedli the. Sketching the region represented by a linear inequality in two. 1 sketch the straight line obtained by replacing the given inequality with an equality. 2 choose a test point not on the line. Sketch the region that corresponds to the given inequality y 33. So 401 does not satisfy the inequality and is not in the solution set shade this side of. The solution set we do not have any points no intersection of bounding lines1 the line is unbounded corner solution set. Sketch the region that corresponds to the given inequities say whether the region is bonded or unbonded and find the coordinates of all corner points if any. Y 22 or y e 2 line line 3 124 6 two points on.
