STA 205 Lecture 3: Homework3

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19 Dec 2018
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12/17/2018 NKU Imath Assessment
https://imath.nku.edu/course/gb-viewasid.php?stu=11461&cid=335&asid=148010&uid=11461 1/10
Grade Book Detail
Damico , Emily
Topic 3: Sampling Distribution of the Sample Proportion
Started: September 13, 2018, 1:52 pm
Last change: September 13, 2018, 4:00 pm
Time spent: 128 minutes
Total time questions were on‑screen: 100.1 minutes.
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Lastyear,66.34%ofNKUstudentswerefromthestateofKY.Repeatedsamplesofstudentswereselected,
andtheproportionofstudentsfromKYineachsamplewasrecorded.Whichofthegraphsbelowwouldbe
thecorrectsamplingdistributionfortheproportionofstudentsfromKYwhensamplesofstudentswere
selected?(Note:Youmayonlyattemptthisquestion2times.Apenaltywillbeassessedonyoursecond
attempt.)
SamplingDistribution1
SamplingDistribution2
SamplingDistribution3
Answer:SamplingDistribution1
Question 1: 2 out of 2 in 1 attempt(s)
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12/17/2018 NKU Imath Assessment
https://imath.nku.edu/course/gb-viewasid.php?stu=11461&cid=335&asid=148010&uid=11461 2/10
Inearly2007theMortgageLendersAssociationreportedthathomeownersweredefaultingontheir
adjustableratemortgagesinrecordnumbers.Theforeclosurerateforthatparticularyearwas1.98%.
a.Toseeiftherehasbeenanychangeintheforeclosurerate,theassociationplanstosample333
homeownerstoseeiftheyareindangerofdefaultingontheirloan.Describethesamplingdistribution
ofthesampleproportionofhomeownerswithadjustableratemortgageswhoareindangerof
defaultingontheirloan.Roundanycalculatedvaluetofourdecimalplaces.
shape:Thesamplingdistributionofthesampleproportion  normally
distributed
Checks:np= andn(1p)=
mean: =
standarddeviation: =
b.Ifthesamplesizeweretoincreaseto1426,whichpartsofthedescriptionofthesamplingdistribution
wouldchange?Selectallthatareappropriate.
Shape
Mean
Standarddeviation
Answer:isnot
Answer:6.5934
Answer:326.4066
Answer:0.0198
Answer:0.0076
Answer:
Shape
Standarddeviation
Question 2: 4.8 (parts: 0.5, 0.25, 0.25, 1, 1, 1.8) out of 5 (parts: 0.5, 0.25, 0.25, 1, 1, 2)in 3 attempt(s)
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12/17/2018 NKU Imath Assessment
https://imath.nku.edu/course/gb-viewasid.php?stu=11461&cid=335&asid=148010&uid=11461 3/10
TheNationalSafetyCouncilreleasedareportin2010stating23.55%ofalltrafficcrashesinvolvedrivers
usingcellphonesandtexting.Thecouncilwouldliketodetermineifthispercentagehasincreasedoverthe
pastthreeyears.Arandomsampleof183trafficcrashesoccurringin2013wasselected,anditwas
determinedwhetherornotthedriverwasusingacellphoneduringtheaccident.
a.Describethesamplingdistributionofthesampleproportionoftrafficcrashesinvolvingacellphone
whensamplesof183trafficcrashesaretaken.Roundanycalculatedvaluestofourdecimalplaces.
shape:Thesamplingdistributionofthesampleproportionis 
Checks(roundto4decimalplaces):np= andn(1p)=
mean: =
standarddeviation: =
b.Thesampleresultedin52trafficcrashesinvolvingacellphone.Wouldthisprovideanysupportfor
theinferencethecouncilisinterestedin?
Thesampleproportionis (roundto4decimalplaces).Thissample
supporttheinferencethecouncilisinterestedinbecauseitis thanthe
proportionreportedin2010.
Answer:normallydistributed
Answer:43.0965
Answer:139.9035
Answer:0.2355
Answer:0.0314
Answer:0.2842
Answer:does
Answer:larger
Question 3: 5 (parts: 1, 0.5, 0.5, 1, 1, 0.5, 0.25, 0.25) out of 5 (parts: 1, 0.5, 0.5, 1, 1, 0.5, 0.25, 0.25)in 1
attempt(s)
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