STA 205 Lecture 9: Packet 9 - Hypothesis Test for the Mean (2)

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chocolateweasel220

19 Dec 2018

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2 set significance level o and give the decision rule. 3 calculate the test and statistic g its associated probability p value score table. Example: the flying pig marathon is held in cincinnati every may. The statcrunch output below summarizes the time it took for all runners in 2012 to finish the 26. 2 mile race. An organizer of the marathon plans to sample 35 finishers from. 2016 to see if the time it takes to complete the race has changed. two sided. Describe the sampling distribution of the sample mean finish time when samples of refers to all. Packet 9: one-sample hypothesis test for the population mean. Textbook pages: 586 589; 597 601. The sample of 35 runners is taken and the sample mean is found to be 4. 569 hours. Use the sample to test the claim made by the organizer at a significance level of 0. 05.

Related Questions

A sample of 36 observations is selected from a normal population. The sample mean is 12, and the population standard deviation is 3. Conduct the following test of hypothesis using the 0.01 significance level: H0: μ ≤ 10 H1: μ > 10

a. Is this a one- or two-tailed test?

b. What is the decision rule, Reject H0 when Z > 2.33 or when Z <= 2.33 ?

c. What is the value of the test statistic? (Round the final answer to 1 decimal place.)

d. What is your decision regarding H0? (Reject or Accept) ?

e. What is the p-value, one, zero, or close to zero ?

amberwalrus562

(1 point) A random sample of 130 observations is selected from a binomial population with unknown probability of success p. The computer value of is 0.64.

(1) Test : : p = 0.65 against : p > 0.65. Use α= 0.05.

test statistic z =

critical z score

The final conclusion is

⭕ A. We can reject the null hypothesis that p = 0.65 and accept that p is > 0.65.

⭕ B. There is not sufficient evidence to reject the null hypothesis that p = 0.65.

(2) Test : p = 0.5 against :p < 0.65. Use α = 0.01.

test statistic z =

critical z score

The final conclusion is

⭕ A. We can reject the null hypothesis that p = 0.5 and accept that p is < 0.5.

⭕ B. There is not sufficient evidence to reject the null hypothesis that p = 0.5.

(3) Test : p = 0.55 against : p ≠ 0.55. Use α = 0.01.

test statistic z =

positive critical z score

oliver202166

I need help conducting a z-test for my assignment. The question states, "You want to determine if Canadians are nicer (less rude) than Americans. Americans 'niceness' score is µ=2.4 with a standard deviation of 1.6. You get a sample of n=36 Canadians to complete the same niceness questionnaire. You calculate descriptive statistics for your sample as M=2.9 and s=1.9. As this is exploratory research, use an alpha of .10. Conduct a z-test on the information above. Make sure to note: 1.) the formula, 2.) the null and alternative hypothesis, 3.) the critical value, 4.) calculate the result (show calculation in case of error), 5.) What is the statistical decision, 6.) What does this mean in plain english?"

Thanks for the help!

yellowimpala697

STA 205 Lecture 9: Packet 9 - Hypothesis Test for the Mean (2)

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