MATH 1150 Lecture Notes - Lecture 5: Constant Term

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=a / 0 a > 0 x x ? x ?) = a 2 + b + c x x. = a h 2 + k (x. , the graph opens upwards like a u. Standard form of a quadratic function: where vertex= (h,k) f (x) When a<0, the graph opens downwards like an n. Complete the square : ( + 4 2 = x2 + 8 + 1 x. So: 8/2=4 x2 + 6 + = ( + 2 x2 + 6 + 9 = (x. Express f(x) in standard form: f (x) (x) f has to be added and subtracted to keep the function value true. 9 cannot just be added, because then it is a different function. (x) f. Next, the 5 needs to be distributed to the -9. 5 + 3 2 4 + 4 = (x. A ball is thrown with an initial velocity of 40ft/s.

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