MATH 110 Lecture 52: Areas Between Curves Examples
Document Summary
Axis, the graph of y = x2 + 4 8 x. Notice that and y = x2 + 4 8 x = 4 x is a parabola opening downward, does not have any. ( x2 + 4 8 x. 1 x2 4 + 8 dx x. 2 8 = 9 y = x + 2 y = x2 4. 2 x3 + 6 1 x | ( 1)2 3 ( 1)3 + 6. = g x (x) x2 4 = 2 1 x x2 2 3 x = 3 1 x x ( 3. To graph x y = x2 4 + 3. This means that at x = 3 it will help to factor it down to y = x2 4 + 3 and x. Intercept at y = 3 and x = 1 y y = x2 4 + 3 x y = 0 and on interval. = x3 3 + 3 x and (x)g.
