PHYS 212 Lecture 1: Coulomb's Law 1/11/17
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Gives force on charge exerts on another. Force of charge 1 on charge 2 = (cid:3044)(cid:2869)(cid:3044)(cid:2870)(cid:3045)2 (cid:1870) . Q2 = charge of object 2 r" = unit vector pointing from 1 to 2 r = distance between the centers of the objects. Qa = +5. 0 nc and is at the origin. B"s charge must be negative (k * 5. 0nc * q2)/16m * + i" = 5. 6 nn. 2 x 10-9 c to find net force on a single charge due to a group of charges: find each individual force acting on the charge using coulomb"s law. Add them all up (using vector addition) Find a place for zero electrical force. Fa on c = -fb on c. Opposite in direction but equal in magnitude for magnitude, c must be closer to smaller of original charges for direction, but c in each region and check. Simplified, the exact position equation becomes: (cid:1869)(cid:883)(cid:2870)= |(cid:1869)(cid:884)| (cid:4666) (cid:4667)(cid:2870) find q1 in terms of q2.
