01:146:356 Lecture Notes - Lecture 22: Skeletal Muscle, Ureter, Exponential Growth

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Systems physiology lecture 11 notes: renal/urinary system (day 3) 1) volume of plasma fluid needed to produce a given amount of solute excreted from the solid. Rate of appearance = rate of disappearance. 2) volume of plasma completely free of any particular type of solute. (concentration * flow) = output clearance?? (per 1 ml) Renal vein and tubular system = two ways to exit. What goes in must equal what comes out. 0 to 700 = range of clearance volume. Pah= (cid:862)para a(cid:373)i(cid:374)o h(cid:455)perate(cid:863) = perfe(cid:272)t 700 = total e(cid:454)(cid:272)retio(cid:374) 0 = the substance is never seen in the urine. Glucose = perfect zero, absorbed basically entirely by the body. Middle amount of excretion is used ot define the rate of renal flow. (cid:272)alled the (cid:862)gf rate(cid:863): glu(cid:373)eria filtratio(cid:374) rate. (cid:862)i(cid:374)uli(cid:374)(cid:863): **(cid:374)ot i(cid:374)suli(cid:374) **, (cid:374)ot a (cid:374)aturall(cid:455) o(cid:272)(cid:272)urri(cid:374)g su(cid:271)sta(cid:374)(cid:272)e. Issue of clearance= black hole= what is happening generally, not in specific sites. Good for general function, not specific functions.

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