BSCI 222 Lecture Notes - Lecture 7: Chromosome
23 Sep 2015
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Bsci 222 - lecture 7 - linkage recombination and mapping. (2 recombinations)/(4 total products) = 50% recombination. Two chromosomes may have multiple recombination events. The farther apart two genes are on a chromosome, the more likely they are to experience multiple recombination events. Colored seeds are dominant to colorless; endosperm full (s) dominant to shrunken (s) Ccss x ccss; or cs/cs x cs/cs. C_ss and ccs_ are parental (or, non-recombinant), because they are the most abundant. If all observed phenotypes were equal, that means they are too far apart on the chromosome or on different chromosomes (i. e. they are unlinked) Since these observed values are unequal, these two genes are linked. Calculate chi-squared; if value is significant, that is evidence of linkage. 149 + 151 = 300 recombinant /8,364 = 0. 0359 = 3. 6%, or 3. 5 cm. Cross homozygous banded, crossveinless, rosy fly with wild-type fly.
