KNES 464 Lecture Notes - Lecture 9: Non-Competitive Inhibition, Enzyme Kinetics, Enzyme

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Lecture 9
V max- on y axis
- Relationship between substrate and rate of reaction
- Plateaus at V max
- Km (units of substrate concentration)
o Substrate concentration at which the ½ V max occurs
Enzyme kinetics
- Sensitivity
- If Km were to steep lower, then line would be steeper
o Small change in substrate concentration results in a larger velocity change at any
given concentration
o The steeper the line, the more sensitivea small change on x axis would give a
bigger change in y axis
Enzymes and Inhibitors
- If you have WAYYYY more enzymes than substrate, then none of the following would
happen
- If change enzyme concentration (add more), then V max is increased, but no change in
km
o Km is a property of the enzymethe km relates to the enzyme, but can increase
V max
- Competitive Inhibitor
o Looks very close to the substrate
o Will go into binding site of the enzyme and block the way for the substrate
(physical barrier)
o Can add so much substrate and kick the inhibitor out
Will affect the km because it will take longer to get to the V max, because
Raise km, because less sensitive
- Noncompetitive Inhibitor
o Will change the enzyme- sometimes it makes it so that the substrate can’t bind
or sometimes it makes it so that the substrate binds, but cannot undergo the
activity of the enzyme
o Binds far from the binding site- do not bind at binding site
o Therefore, V max is affected (lower because less place for them to go)
If have noncompetitive inhibitor, it will be on that enzyme no matter how
much enzyme
Substrate cannot outcompete the enzyme becayse it is not there
Km does not change
o Sensitivity is the same but V max is lower
V max
Km
More Enzyme
Increase
No change
Competitive Inhibitor
No change
higher
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Document Summary

Relationship between substrate and rate of reaction. Km (units of substrate concentration: substrate concentration at which the v max occurs. If you have wayyyy more enzymes than substrate, then none of the following would happen. If change enzyme concentration (add more), then v max is increased, but no change in km: km is a property of the enzyme the km relates to the enzyme, but can increase. If have noncompetitive inhibitor, it will be on that enzyme no matter how much enzyme: substrate cannot outcompete the enzyme becayse it is not there, km does not change, sensitivity is the same but v max is lower. Amount of energy required or released required by the reaction is a function of how far it is from equilibrium. At equilibrium- gibbs free energy is 0: no net movement. Mass action ratio: ratio of concentration of product over the concentration(s) of reactant(s, r= [b]/[a, atp adp + pi, r= [adp] x [pi]/ [atp]

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