BIS 2B Lecture Notes - Lecture 12: Dihybrid Cross, Allele Frequency, Genotype Frequency

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Imagine that you have three loci, each has two alleles that sort independently: yellow/green (y/y) peas; smooth/wrinkled (ss) peas; purple flowers/white flowers (pp) Take a true breeding yellow, wrinkled, white flowered plant and cross it to a true breeding green smooth purple one to make the f 1 . Now cross the f 1 "s to get an f 2. Green , smooth , purple flowered . Given allele frequencies for a dominant trait of 0. 6, with only a single recessive trait, what do you expect genotype frequencies at hardy-weinberg equilibrium (cid:262)(cid:625)aa(cid:626)=. (cid:546)6, (cid:262)(cid:625)aa(cid:626)=(cid:547)(cid:551), (cid:262)(cid:625)aa(cid:626)=(cid:544)6. F(cid:327)e(cid:326)ue(cid:300)cy o(cid:262) this t(cid:327)ait (cid:299)ust be (cid:544)-. (cid:544)6= . 84. X h y= (cid:552)(cid:545)% (cid:326)= (cid:262)(cid:625)x h (cid:626)=. (cid:543)(cid:551) p= (cid:262)(cid:625)x h (cid:626)=. (cid:552)(cid:545) (cid:262)(cid:625)x h x h (cid:626)= (cid:326) (cid:545) = (cid:625). (cid:543)(cid:551)(cid:626) (cid:545) = . (cid:543)(cid:543)6(cid:547) Hardy-weinberg equilibrium assumes: large (infinite) population, random mating, no gene flow from other populations, no new mutations, no natural selection! Mutation: the source of all novel genetic variation.

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