STA 2023 Lecture Notes - Lecture 12: Sickle-Cell Disease, Royal Institute Of Technology
Document Summary
As many as one in every 500 african americans in the us are reported to have sickle cell anemia. One in 10 is a carrier of the trait, and carriers who marry have a 1 in 4 chance of passing the disease to their children. Suppose a carrier has three children and the transmission of the disease from the carrier to any one child is independent of whether or not the carrier transmits to another. P (c1: = does not have it, none of the children acquire the disease. c c3 c c2. P(a b) = p(a) p(b: p(c3. P(c1: p(c2, = (3/4) (3/4) (3/4) = 27/64, all three acquire the disease. P(c1 c c2: p(c3 c c3, = (1/4) (1/4) (1/4) = 1/64, exactly one acquires the disease. P (one) = p(only child 1) + p(only child 2) + p(only child 3) ***all fractions inside parenthesis come from the answers from questions a-c.
