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Lecture 5

LING 165C Lecture Notes - Lecture 5: Phrasal Verb, Identity Function, Beagle


Department
Linguistics
Course Code
LING 165C
Professor
Dylan Bumford
Lecture
5

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- Homework 9.3 (c)
- The two expressions have no extra free variables. Every single variables are
bound
- They get the same result at every assignment
- Example
- The beta conversion of the above expression λx[walk’(x)](j) is walk’(j)
- Subtype, small-clause
- (john is sad)
- Mitka (is obedient)
- where (is obedient) is a VP which is equivalent to S/LNP
- Obedient is a function that takes in an entity and returns a truth value. Its
a property that tells is whether something have or something don’t
- S/NP takes in a NP from the domain and return something S. By that logic
“Mitka(NP
) obedient(S/NP
)” is a sentence, but in reality it is not.
- Even though Mitka obedient can’t stand alone as sentence, but when we
placed in inside another sentence, it works.
- With Mitka obedient finally we can get to sleep”
- I prefer Mitka obedient
- Because of this, we need subtypes, i.e restrict what is returned by combination
from Mitka obedient
- In the example above, we will enforce verbs like with” and prefer to take in
small-clause. In this case we have (S/LNP)/RS[A]. The verb takes in a small clause
of S[A], and puts it to the right of the sentence. A for adjective
- Example of small-clause
- John put [the book] [on the table]
- The verb put has ((S/LNP)/RPP[ON])/RNP. The [on] just enforces a PP that starts
with the prepositional verb on
.
- Formalization
- Mitka is obedient
- Mitka is NP, and obedient is S[a]/LNP. Now we need to know what category is is
- We know is as <<e, t>, <e, t>> which is an identity function, which means it
doesn’t do anything semantically
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