MATH 4B Lecture 2:
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Last time: diagonalized the matrix a = i "s is we had a basis of eigenvectors which allow us to diagonalize a. Theoremclay by hamilton ) holds of matrices well as the for diagonal representation det la - xis ) = h - 2x - 3 char . poly . p. La - xis ) p =p de "t. D= i to 9 ) has char . poly f- > span get , e "t be defined as. I best ae this defines a transformation c not operator vector. Ta is acting as a derivative ddett = From above, we can imagine a the derivative transformation as being represented by d. This diagonal representation is connected to a by the matrix. 2 d - 3 is )j=j . I function of t is a zero transformation pay - spy - zy = o s zero tuition another notation : y.