AMS 5 Lecture Notes - Lecture 12: Normal Distribution, Css Box Model

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AMS 5 Full Course Notes
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*note: there was no class monday due to a protest. B, so p(red and b) = 30/100 = 30% Or: 40% of the marbles in the urn are red, and of these red marbles, 75% are marked with a b, so. P(red and b) = (40%) * (75%) = 30: in other words. P(red and b) = p(red) * p(b | red: the multiplication rule. P(e and f) = p(e) * p(f | e: also. P(e and f) = p(f) * p(e | f: example 6: three cards are dealt from the top of a well-shuffled deck. A< so p(a) = 25: tere are 120 x-tickets and 30 of them are marked with an a< so p(a | x) So, if e and f are independent events, then the multiplication rule reduces to: in fact, this formula can be used as the definition of independence.

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