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Lecture 7

# MATH 11 Lecture 7: 41717 Lecture Notes (7) Premium

6 Pages
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School
University of California - San Diego
Department
Mathematics
Course
MATH 11
Professor
David James Quarfoot
Semester
Spring

Description
4/17/17 Lecture Notes (7) Friday, April 21, 2017 12:58 PM • If P (A or B)= P(A) + P(B), if A and B are disjoint P (A and B) = P(A)xP(B), if A and B are independent Losing Disjointness! More General Rule: P(A or B) = P(A) + P(B) - P(A and B) If so if •it In probability class, "A or B" includes three ideas: 1) A, but not B, 2) B, but not A, 3) both A and B In everyday speech, "A or B" can mean this same thing ["inclusive or"], or sometimes it means just two ideas 1) A, but not B, 2) B, but not A ["exclusive or"] Ex. Coffee or tea? Example: 80% of college students like learning. 70% of college students like video games. 62% like both learning and video games. What percent like learning or video games? Let L be the event that a college student likes learning Let V be the event that a college student likes video games P(L or V) = P(L) + P(V) - P(L and V) = 0.8 +0.7 - 0.62 =0.88 0.62 0.12 Describe the words the zone given by: 0.18: People who like learning but not video games 0.08 + 0.62 : People who like video games 0.12: People who dislike learning and video games 0.18 + 0.08 : People who like learning or video games but not both. Contingency Tables: A Venn diagram alternative H Like Video games Dislike video games Margin totals Like learning 0.62 0.18 0.80 Dislike learning 0.08 0.12 0.20 Margin totals 0.70 0.30 1.00 Joint probability: the probability of two things joining forces an happening simultaneously. For example, 8% of students hold the joint opinion that learning is boring and video games are fun Marginal Probabilities: the probability of one value of a categorical variable occurring, for example 80% of students like learning,. These values are the sum of the joint probabilities in a row or column. A harder example A teacher surveys the class about Twitter and Instagram use. Of the students, 20 use both, 10 use neither, 72 don’t use Instagram, and 38 don’t use Twitter. What is the probability that randomly chosen student will be on Instagr
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