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PHYS 1B Lecture Notes - Lecture 2: Test Particle, Electric Field, Net Force

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coffeecamel142
10 Jan 2018
School
UCSD
Department
Physics
Course
PHYS 1B
Professor
Philbert Tsai

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Document Summary

So we know that opposites attract and like charges repel. We"ll choose the +x direction to point to the right. Calculate the net force on particle q1 due to the other two charges (q2, q3) List all the known quantities in the problem. Calculate the magnitude of each force separately using. Q1 and q2 have opposite charges, so f21 is attractive, which means that f21 pulls q1 in the. Q1 and q3 have like charges, so f31 is repulsive, which means that f31 pushes q1 in the -x direction. Consider four charges arranged in a square pattern as shown. Calculate the magnitude and direction of the net force on the top-left charge (q1) due to the other three charges. We want to calculate an electrical force on a charge. What tools do we have to accomplish that task. Step 0(d) (i) do we have that information? (ii) if not, how do we get that information? (i) mostly.

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

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Related Questions

<p>In the figure, four particles are fixed along an x axis,separated by distances d = 7.00 cm. The charges are q1 = +1e, q2 =-e, q3 = +e, and q4 = +4e, with e = 1.60 10-19 C. In unit-vectornotation, where right is the + direction, what is the netelectrostatic force on each particle below due to the otherparticles?<br /><br />I am very very confused by thisproblem.</p>
<p>I figured that you would set this up like but am unsure ofthe q2 value since its Negative. I believe it only refers todirection.</p>
<p>&#160;</p>
<p>F1 = F(12) + (F13) + F(14)&#160;</p>
<p>F(12) = (8.99*10^9)(1.6*10^-19)(1.6*10^-19) /.07^2</p>
<p>F(13) = (8.99*10^9)(1.6*10^-19)(1.6*10^-19) /.14^2</p>
<p>F(14) = (8.99*10^9)(1.6*10^-19)(6.4*10*-19) /.21^2</p>
<p>&#160;</p>
<p>Also it is wanting me to answer in Vector Notation?HUH</p>
<p>&#160;</p>
<p>&#160;</p>

Learning Goal: To work through astraightforward application of Faraday's law to find the EMF andthe electric field surrounding a region of increasing flux

Faraday's law describes how electric fields and electromotiveforces are generated from changing magnetic fields. This problem isa prototypical example in which an increasing magnetic fluxgenerates a finite line integral of the electric field around aclosed loop that surrounds the changing magnetic flux through asurface bounded by that loop. A cylindrical iron rod withcross-sectional area is oriented with its symmetry axis coincidentwith the z axis of a cylindrical coordinate system as shown. It hasa uniform magnetic field inside that varies according to . In otherwords, the magentic field is always in the positive z direction,and it has no other components.

For your convenience, we restate Faraday's law here: , where is theline integral of the electric field, and the magnetic flux is givenby , where is the angle between the magnetic field and the localnormal to the surface bounded by the closed loop.
Direction: The line integral and surface integral reverse theirsigns if the reference direction of or is reversed. The right-handrule applies here: If the thumb of your right hand is taken along ,then the fingers point along . You are free to take the loopanywhere you choose, although usually it makes sense to choose itto lie along the path of the circuit you are considering.

Find , the electromotive force (EMF) around a loop that is atdistance from the z axis, where is restricted to the region outsidethe iron rod as shown. Take the direction shown in the figure aspositive.
Express in terms of , , , , and any needed constants such as , ,and .
Due to the cylindrical symmetry of this problem, the inducedelectric field can depend only on the distance from the z axis,where is restricted to the region outside the iron rod. Find thisfield.
Express in terms of quantities given in the introduction (andconstants), using the unit vectors in the cylindrical coordinatesystem,r^ ,theta^ , and z^ .