PHYS 211 Lecture Notes - Lecture 12: Massachusetts Route 2, Headon
8 Oct 2015
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When internal forces acting during a collision are only conservative forces. Speed of objects will remain unchanged, only directions will be affected. K1,initial = k1, final + k2, final. Transform and solve in the center of mass frame. We will see how to do this in the next example. Ptotal, initial = ptotal, final = 0. Plug in corresponding values from the conservation of momentum for (mv*) terms to get equation in regards to one variable. (m1v* Cancel same values on each side then take the square root of both sides. Mvi)/ mtotal = (m1v1+m2v2)/ m1 + m2. V2, initial = 0 m/s m2 = 3 kg. Second object is at rest, this is 1-dimensional motion. Vcm, lab = [2kg(5m/s) + 3kg(0m/s)] / (5 kg) V1, final = -3 m/s + 2 m/s = -1 m/s. V2, final = 2 m/s + 2 m/s = 4 m/s. 1,i = 5 m/s - 2m/s = 3 m/s.
