CHEN 3005 Lecture Notes - Lecture 1: Itta Of Metz, Opata Language, Vehicle Identification Number

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Navier-stokes eqn has 2 parts mass conservation (density is a constant) scalar vector vector laplacian = scalar, but velocity = vector this is all vector, each part has 3 components so this isn"t 1 eqn, it"s really 3 eqns. 1 top plate moves we solved using shell balancenow using eqn above: gradient in cartesian coordinates. Chen transport page 1: gradient in cartesian coordinates. Navier-stokes eqn allows us to solve an unsolvable eqn. 2 boundary conditions vx(y = 0) = 0 vx(y = h) = u means no slip ex. 2 boundary conditions: vx(y = 0) = 0 vx(y = h) = 0. Chen transport page 4 magnitude of velocity dependency of velocity on y what if translate coordinate axis into center of pipe? (in red) y" = y - h/2 --> y = y" + h/2 plug it to convert eqn.

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