CHEM 2301 Lecture Notes - Lecture 23: Pi Bond, Propionate, Stereoselectivity
Document Summary
Chem-2301 lecture 22 notes-chapter 7. 10 -7. 12alpha and beta carbons. One carbon next door to alpha carbons. Above diagram taken from google, helps explain the concept more visually. Step one figure out beta and alpha positions. Beta carbons on each side are identical to each other. Step 2 eliminate hydrogens along with the water molecule. Option 1: drive equilibrium towards formation of product. Option 2: remove other product through distillation. In terms acid catalyst being used, you should use constipated acid. If a starting material has 2 different kinds of beta hydrogens, then there would be stereoselectivity selection. Each position different because the are connected to different things. If beta 1 is removed, product would be, between two molecules. Product = some kind of alkene. = trisubstituted. 7. 12 mechanisms for alcohol dehydration elimination reactions. 1 is less than 2 is less than 3. E1 for 2 degree and 3 degree alcohol.
