MATH 2574H Lecture : Discussion 242014.pdf
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Solve for y: xy" = 2y + x3cosx y" - (2/x)y = x2cosx. Integration factor: eintegrate[(-2/x)dx] = e-2lnx = x-2 x-2y" - 2x-3y = cosx (x-2y)" = cosx x-2y = integrate[cos(x)dx] = sin(x) + c y = x2(sin(x) + c) Find function f(x,y) so that m(x,y) + n(x,y)(dy/dx) = dx + dy = c. F = integrate[mdx] + h(y) x2y" = y + sqrt[x2 + y2] Y - sqrt[x2 + y2] + x2y" = 0. F = -integrate[(y + sqrt[x2 + y2])dx] h(y) x = ytan(u) dx = ysec2(u)
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