BIT 3414 Lecture Notes - Lecture 17: Joule

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Order for workstation 1: process 100 units of component x. % of available working time spent processing jobs. Efficiency how well the worker or machine performs compared to a standard. Load the amount of work (units of time) assigned to a workstation. Load percent the ratio of load to capacity = (100%) load capacity. Jobs to be done next week (all times in minutes): Load % = 100% = 4300/capacity (100%) => capacity = 4300mins. Load % = 90% = 4300 / capacity (100%) => capacity = 4300/90 (100) = A new order for 100 parts must be completed as fast as possible. Two machines (two separate operators) are capable of processing the order. Option 1: split 50:50 between lathe and mill: >max of 2 times 545mins so the mill is the less efficient station. Option 2: optimal split between lathe and mill: >max of 2 times 370mins so the lathe is the more efficient station.

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