BIO 230 Lecture Notes - Lecture 26: Mendelian Inheritance, Meiosis, 2Degrees
16 Jan 2017
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Notes from powerpoint chapter 3 first slide about family inheritance (2nd slide of chapter 3) Martha"s great gra(cid:374)d(cid:373)other has disease, gra(cid:374)d(cid:373)other is a (cid:272)arrier, Assume that anyone married that is not labeled is homozygous dominant (gg) (cid:373)ultiple all the (cid:272)ha(cid:374)(cid:272)es together to get (cid:272)ha(cid:374)(cid:272)e of (cid:373)artha a(cid:374)d joh(cid:374)"s (cid:272)hild. X x x = 2/48 = 1/24. Chi square equation 2 = (o e)2/e. Memorize this equation and the setup of chart for exam! Chart in order from left to right: class (what is being tested), observed number (o), expected number (e), (o-e)2, (o-e)2/e. Example: if there are red, white, and pink flowers that means the degrees of freedom is 2 because df=3-1. 2 phenotypes - 1 = 1 degrees of freedom. 3 phenotypes - 1 = 2 degrees of freedom. 4 phenotypes - 1 = 3 degrees of freedom. 8 phenotypes - 1 = 7 degrees of freedom. Recombination: production of new allele combinations that happen by
