L07 Chem 151 Lecture Notes - Lecture 12: Molar Mass, Hygroscopy, Desiccator
23 Feb 2017
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[h+] = 2. 34 x 10-3 m; ph = -log[h+] = 2. 631 ph = 5. 82; [h+] = 10-5. 82 = 1. 5 x 10-6. Z = log(x)/ln(10) dz = (1/ln10)(dx/x) dz: absolute error in z; dx/x: relative error in x. E = c1ph + c2 c1 and c2 are condition dependent, so the meter must be calibrated. The glass bulb on the probe is very fragile. Adding an equivalent amount of titrant to react with analyte. Equivalence point where the amount of titrant exactly consumes the analyte. Determined using an indicator that changes color at the end point i. e. indicates that equivalence has been reached. By measuring the volume of titrant added, moles of titrant added: Moles t= mt*vt in l = moles of analyte. Either the titrant or analyte must be a standard solution. Solid naoh is hygroscopic, therefore not a primary standard. Naoh is also not stable, so an accurate concentration must be calculated.
