L07 Chem 151 Lecture Notes - Lecture 13: Titration Curve, Protonation, Equivalence Point

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Equilibrium: ha + h2o -> approx. x[a-]/[ha]0. Equilibrium shifted dramatically left due to the common ion. +]0 + x)/([nh3]0 x) -> approx. x[nh4+]0/[nh3]0. Equilibrium shifted left, poh is given by x. Buffer solutions weak acid at equilibrium with a weak base e. g. ha + a-, b- + hb+ can come from the dissociation of a salt. Henderson hasselbach equation ph = pka log([ha]eq/[a-]eq) When x is very small (in the case of buffers) equilibrium is shifted right. Works best when [ha] is very close to [a-] Further apart the concentrations are, the less accurate the equation is. 10:1 ratio of acid:base or base:acid is the limit. Titration curve of a strong base with a weak acid. Protonated and deprotonated forms are different colors ph = pka log([hin]eq/[in-]eq) To find the pkin -> look for max/min ph at which only first color/second color is visible and find midpoint.

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