You genotype a C/T SNP from a sample of narwhals (*Monodon monoceros*) from the arctic at two locations, Canada and Siberia, and get the following genotype frequencies.

Canada

c-/c- 9

c+/c- 26

c+/c+ 30

Siberia

c-/c- 28

c+/c- 32

c+/c+ 15

A) What is the frequency of the c- allele in each population?

B) What fraction of heterozygosity is missing (*F**IS*) in each population?

C) What is the average of the expected frequency of heterozygotes over all populations (*H**S*)?

D) What is the average allele frequency over all populations?

E) What is the total expected heterozygosity frequency (*H**T*)?

F) What is the fraction of heterozygosity missing due to differences in allele frequencies between populations (*F**ST*)?

You genotype a C/T SNP from a sample of narwhals (*Monodon monoceros*) from the arctic at two locations, Canada and Siberia, and get the following genotype frequencies.

Canada

c-/c- 9

c+/c- 26

c+/c+ 30

Siberia

c-/c- 28

c+/c- 32

c+/c+ 15

A) What is the frequency of the c- allele in each population?

B) What fraction of heterozygosity is missing (*F**IS*) in each population?

C) What is the average of the expected frequency of heterozygotes over all populations (*H**S*)?

D) What is the average allele frequency over all populations?

E) What is the total expected heterozygosity frequency (*H**T*)?

F) What is the fraction of heterozygosity missing due to differences in allele frequencies between populations (*F**ST*)?

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### Related textbook solutions

## Related questions

1. Data from the caffeine metabolism experiment was pooled together using information from internal and external students across a number of years. The data collected is summarized in the table below. The genotypes are shown in the first column and the other two show the number of genotypes in the two categories of caffeine tolerance (tolerant/intolerant â the classes are derived from the questionnaire data). Use the data in this table to answer this question and others throughout the quiz.

Genotype | Tolerant | Intolerant |

AA | 148 | 37 |

AC | 106 | 99 |

CC | 83 | 137 |

What are the genotype frequencies using data from all the individuals measured in this experiment?

Select one:

a. AA=0.40 AC=0.44 CC=0.16

b. AA=0.165 AC=0.439 CC=0.396

c. AA=0.25 AC=0.50 CC=0.25

d. AA=0.303 AC=0.336 CC=0.361

2. What are the allele frequencies using all individuals in the experiment?

Select one:

a. A=0.5 C=0.5

b. A=0.471 C=0.529

c. A=0.371 C=0.629

d. A=0.25 C=0.75

3. What are the expected genotype frequencies under Hardy-Weinberg equilibrium?

Select one:

a. AA=0.25 AC=0.5 CC=0.25

b. AA=0.333 AC=0.333 CC=0.333

c. AA=0.222 AC=0.498 CC=0.280

d. AA=0.166 AC=0.668 CC=0.166

4. Test if the population is in equilibrium using a chi-square test. What is the chi-square value for this population?

5. What is the correct number of degrees of freedom for the chi-square test from the previous question?

6. Is this population in Hardy-Weinberg equilibrium?

Select one:

True

False

7. What is the genomic location of CYP1A2?

Select one:

a. 21p24.1

b. 7q24.1

c. 15p24.1

d. 15q24.1

8. What is the reported world-wide frequency for the C allele in human populations?

9. Test if the allele frequencies in our population are significantly different from the world-wide frequencies using a chi-square test.

Select one:

a. chi-square = 131.44; 1 degree of freedom, our population's allele frequencies are significantly different from the world-wide estimates

b. chi-square = 1.314; 1 degree of freedom, our population's allele frequencies are not significantly different from the world-wide estimates

c. chi-square = 1.314; 2 degrees of freedom, our population's allele frequencies are not significantly different from the world-wide estimates

d. chi-square = 131.44; 2 degrees of freedom, our population's allele frequencies are significantly different from the world-wide estimates

10. Use a chi-square independence test to determine if the genotypic frequencies differ between the tolerant and intolerant individuals. The chi-square value is: