Calculate the volume of 0.326 M potassium hydroxide required to neutralize 26.0 mL of a 0.305 M hydroiodic acid solution.

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Irving HeathcoteLv2

13 Dec 2019

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What volume of a 0.110 M calcium hydroxide solution is required to neutralize 25.5 mL of a 0.193 M hydroiodic acid solution?

A student is asked to standardize a solution of sodium hydroxide. He weighs out 0.920 g potassium hydrogen phthalate (KHC8H4O4, treat this as a monoprotic acid). It requires 29.5 mL of sodium hydroxide to reach the endpoint.

A.) What is the molarity of the sodium hydroxide solution? 0.153 M This sodium hydroxide solution is then used to titrate an unknown solution of hydroiodic acid.

B.) If 10.7 mL of the sodium hydroxide solution is required to neutralize 25.0 mL of hydroiodic acid, what is the molarity of the hydroiodic acid solution? 0.357 M

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Calculate the volume of 0.326 M potassium hydroxide required to neutralize 26.0 mL of a 0.305 M hydroiodic acid solution.

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