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Torque can be calculated by multiplying the force (N) applied at 90∘ to the lever arm at a distance (m) from the pivot point (point of rotation), the compound SI unit for the torque is N⋅m. If the force (at 90∘ to the lever arm) applied is 15 N and it is applied at 2.0 m from the pivot point (point of rotation), what is the torque on the lever?

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Related questions

Problem 1. Consider a polymer molecule made up of N segments (monomers) of length l. We would like to build a 1D model to show how a single polymer molecule responds to forcef applied at its two ends. Many laboratories can now perform these experiments on single biopolymers such as DNA or proteins, or svnthetic polymers such as polyethyleneglycol (PEG. The polymer molecule reaches it length L (end-to-end distance) through a series of steps of length I taken in either positive or negative direction. Then each micro-state can be represented by a series of such steps, e.g. for L-3, two possible configurations are: When a molecule is stressed, each segment can align along or against applied force (since it is a 1D polymer, no other angles are allowed). Then the energy of a segment E - (force)(segment projection in the direction of force) can be represented by ε the force (i.e. having projected segment lengths -l or +l, respectively; ) fl and ε+-ザ1 for segments oriented anti-parallel or parallel with Find dependence of InW on the number of anti-parallel and parallel segments n_ and n+. Sketch (or plot using software of your choice) T versus U. Allow U to be both positive and a. b. Express Tfor the system of N segments having total energy U under applied force f. c. negative. Note that the overall length now has a direction (against or along applied force) and can be between -L and L. Comment on vour observations. d. Express U(T, N,jf) e. At fixed temperature, find the total polymer length L (defined as Las a function off.

1. When an open-end manometer is attached to a tank of gas in which the pressure is 1.030 atm which of the following will be observed if the barometric pressure is 0.980 atm? (Conversion factor: 1 atm = 760 torr)

a.The mercury level in the open arm of an open-end manometer will be 19 mm above a reference point.

b.The mercury level in the open arm of an open-end manometer will be 38 mm above a reference point.

c.The mercury level in the arm connected to a tank of gas will be 19 mm above a reference point.

d.The mercury level in the open arm of an open-end manometer will be 38 mm below a reference point.

e.The mercury level in the arm connected to a tank of gas will be 38 mm below a reference point.

2. A 15.0 L bulb containing Ar at 5.0 atm and a 22.0 L bulb containing Kr at 7.0 atm are connected by a stopcock. What will be the partial pressure of Ar in the mixture when the stopcock is opened and gases are allowed to mix at a constant temperature?

a.4.9 atm b.2.0 atm c.5.0 atm d.3.0 atm e.0.41 atm

3. A gaseous mixture contains equal masses of CO2, CO, N2, and O2. If the total pressure of the mixture is 1.00 atm what can be said about partial pressures?

a.Partial pressures of all gases are equal to 0.25 atm.

b.Partial pressure of N2 is smaller than partial pressure of O2.

c.Partial pressure of O2 is greater than partial pressure of CO.

d.Partial pressure of CO is more than 0.25 atm

e.Partial pressure of CO2 is greater than 0.25 atm.

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27) If an 0.880 m aqueous solution freezes at –3.50 °C, what is the van\'t Hoff factor, i, of the solute? Kf values can be found here.

26) Assuming 100% dissociation, calculate the freezing point and boiling point of 2.75 m Na2SO4(aq). Constants may be found here.

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