How do you evaluate sin(π/6)?
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consider the following. x = sin 1/ 2 θ , y = cos 1/ 2 θ , −π ≤ θ ≤ π,;
(a) Eliminate the parameter to find a cartesian equation for the curve.
(b) How does the curve look?
How do you find the value of cos〖(π/3)〗?
