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Chemistry
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11 Dec 2019

using the unit conversion method derive an eqauation tocalculate the heat produced from the HCl-NaOH reaction, and writeyour equation in sample caculation A.

I do not think it is detal H equation.

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Nelly Stracke
Nelly StrackeLv2
13 Dec 2019
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Related questions

A 12.63-mL sample of aqueousNH3 was reacted with 50.00-mL of 0.1025 M HCl. Theexcess acid is then neutralized by titrating the sample to aphenolphthalein end-point with 25.98-mL of 0.1445 M NaOH. Thismethod is known as an indirect method of analysis.

a. Explain why the reaction between NaOH and HClallows you to determine the molarity of the NH3solution.

b. Show the series of calculations required tocalculate the molarity of NH3 in the aqueoussolution.

A 12.63-mL sample of aqueousNH3 was reacted with 50.00-mL of 0.1025 M HCl. Theexcess acid is then neutralized by titrating the sample to aphenolphthalein end-point with 25.98-mL of 0.1445 M NaOH. Thismethod is known as an indirect method of analysis.

a. Explain why the reaction between NaOH and HClallows you to determine the molarity of the NH3solution.

b. Show the series of calculations required tocalculate the molarity of NH3 in the aqueoussolution.

• 50.5 kJ of heat is released when 1 mole of HCl reacts with 1 mole of NaOH to produce 1 mole of NaCl and 1 mole of H2O. Write a thermochemical equation for this reaction.
•The equation below shows that dissolving 1 mole of NaOH in water releases 40.05 kJ of heat (q). What if there was 2 moles of NaOH, how much heat would be released (q)?
NaOH(s) ​​​​Na+(aq)​+​OH-(aq)​​+​40.05 kJ
• From the equation above, calculate the amount of NaOH that needs to be dissolved (in moles) in order to release 1000 kJ of heat (q).
• What should happen to the temperature of the solution produced from dissolving NaOH(s) in distilled water?
• Write the following sentence as a chemical equation:
“When 1 mole of HCl(aq) neutralizes 1 mole of NaOH(aq), 100.1 kJ is released”

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