Textbook ExpertVerified Tutor
9 Nov 2021
Given information
Here, the mean for the given distribution(μx)=$44,000;
the standard deviation (σx)=$6,500;
Sample size(n)=10;
Step-by-step explanation
Step 1.
For, the 90th percentile for an individual teacher's salary;
NORM.S.INV(0.9)=1.281552;
So, P(Z<1.28)=0.90;
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