ivoryfrog948Lv1
13 Nov 2021
Problem 66
Page 119
Section: Problems by Topic
Chapter 3: Molecules, Compounds, and Chemical Equations
Textbook ExpertVerified Tutor
13 Nov 2021
Given information
sample of phosphorus reacts with selenium to form 
of the selenide.
Step-by-step explanation
Step 1.
Empirical formula of a chemical compound is the simplest whole no. ratio of atoms present in a compound .
Empirical formula is determined by calculating the mass of constituent atoms , then from the mass of the constituent atoms their corresponding no. of moles and finally taking the simple integral ratio between the no. atoms .
Mass of phosphorous 
Mass of selenide 
Phosphorous reacts with selenium to form phosphorous selenide.
According to law of mass action sum of the mass of the products will be equal to the sum of the mass of the products.
Thus,
Mass of selenium
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