Given information
It is given that the two speakers are separated by the distance (
) of 
and are set on the frequency (
) of 
. A microphone is being placed at the perpendicular from the midpoint of the speaker's separation. The speakers are reconnected so that the sounds they emit are exactly out of phase.
Step-by-step explanation
Now, the frequency is again set at but this time the sound waves are out of phase, means there will be a phase difference due to which the the maxima and minima intensity of the sound in the line of microphone will changed. We already find the position at which there will be minimum intensity (suitable position for microphone) in when speakers are in phase in (a). The distance is comes out to be 
rightward (even the minima intensity can be on leftward with same distance) from the previous position of mic.
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Physics: Principles with Applications
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- Problem 1
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