Question

Problem 27b

Answer 1

Given information

Given:-

critical numbers

 

Step-by-step explanation

Step 1.

we have found the first derivative of the function in part one.

Now, To find the local maximum and minimum values of the function we determine the intervals around the critical numbers.

if we put the value of in the derivative we found the intervals  

if we put the value of in the derivative. so there is not any relative extremum at this point.

now choose one point from each of them 

 

 

 

so the function has a local minimum value at,

now put the value of   in the given function