A capacitor stores charge Q at a potential difference ΔV. What happens if the voltage applied to the capacitor by a battery is doubled to 2 ΔV?
(a) The capacitance falls to half its initial value, and the charge remains the same.
(b) The capacitance and the charge both fall to half their initial values.
(c) The capacitance and the charge both double.
(d) The capacitance remains the same, and the charge doubles.