A force of -9000 N is used to stop a 1500 kg car travelling at 20 m/s. What braking distance is needed to bring the car to a halt?

Newton's second law: F = m x a

(=) -9000 = 1500a
(=) a= -6 m.s-2

When the car stops, velocity = 0 and the car's initial speed is 20 m/s

V0 = initial veloc.
V = final veloc.

s=1500x(20)^2/(2x9000)

=33.33m

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