🏷️ LIMITED TIME OFFER: GET 20% OFF GRADE+ YEARLY SUBSCRIPTION →
Log in
Physics
2
answers
0
watching
283
views
27 Dec 2020

A point charge causes an electric flux of -1.0 x 103 Nm2/C to pass through a spherical Gaussian surface of 10 cm radius centered on the charge.

What is the value of the point charge?

Booster class
Electricity and Magnetism
Skill
Understanding Gauss’s law
Watch
2
answers
0
watching
283
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Share
Supratim Pal
Supratim PalLv10
27 Dec 2020
Already have an account? Log in
Share

Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

Gauss' Law states that the electric flux through a closed"Gaussian" surface equals the net charge inside divided by theconstant
where C2/(N m2).
(a) Suppose that a charge -3.0 nC is located at the origin, andthat the Gaussian surface is a sphere of radius 15.0 cm centered onthe origin. What is the electric flux through the sphere?
N m2/C
(b) The Gaussian sphere is shifted so that its center is at x = 5.0cm. What is the flux now? N m2/C

(c) The Gaussian sphere is shifted so that its center is at x =35.0 cm. What is the flux now?
N m2/C
(d) A new Gaussian sphere is used of twice the original radiuscentered on the origin. What is the flux now?
N m2/C
(e) A new Gaussian surface is a tetrahedron centered on the originwith sides of length 15 cm. What is the flux now?
N m2/C

(f) A second charge +4.5 nC is added located at x = 17.0 cm. AGaussian sphere of radius 15.0 cm is centered on the origin. Whatis the flux through the sphere?
N m2/C

(g) The sphere in part (f) is now centered at x = 5.0 cm. What isthe flux through the sphere?
N m2/C

A Gaussian sphere of radius 6.30 cm is centered on a ball that hasaradius of 1.30 cm and a uniform charge distribution. The total(net)electric flux through the surface of the Gaussian sphere is+8.00 x104 N·m2/C. What is theelectric potential (inV) 14.0 cm from the center of the ball?

Figure shows a spherical Gaussian surface and a charge distribution. When calculating the flux of electric field through the Gaussian surface, the electric field will be due to

Weekly leaderboard

Home
Homework Help 3,900,000
Physics 110,000
Start filling in the gaps now
Log in