1
answer
0
watching
273
views
30 Dec 2020
A parallel-plate vacuum capacitor is connected to a battery and charged until the stored electric energy is U. Then a dielectric material with dielectric constant K is inserted into the capacitor, filling the space between the plates. The battery is then disconnected and the capacitor is discharged through the resistor. For this situation,what is , the energy dissipated in the resistor?
A parallel-plate vacuum capacitor is connected to a battery and charged until the stored electric energy is U. Then a dielectric material with dielectric constant K is inserted into the capacitor, filling the space between the plates. The battery is then disconnected and the capacitor is discharged through the resistor. For this situation,what is , the energy dissipated in the resistor?
Supratim PalLv10
30 Dec 2020