PCS 211 Study Guide - Final Guide: Test Particle, Electric Field, Loa

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14 May 2017

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The electric force exerted on q2 due to a charge q1: For magnitude: |f21| = ke|q1||q2| / r2 q1, q2: charges on the two particles (+ or -) r: distance between two particles r : a unit vector directed from q1 to q2 ke: coulomb constant = 8. 9875(cid:1)109 n m2/c2. 0(cid:1) = 8. 8542(cid:1)10-12 c2/n m2, permittivity of free space. Multiple charges: f1 = f12 + f13 + f14 + q1 q2 q3. | q3 || q2 | a 2 a2 x (cid:4) = 8. 99 (cid:2) 109 n (cid:3) m 2 (cid:8) C2 (cid:5) (cid:6) (cid:9) (cid:7) (5 (cid:2) 10 (cid:1)6 c)(2 (cid:2) 10 (cid:1)6 c) (0. 1 m) 2. | q3 || q1 | ( 2a)2 (cid:4) = 8. 99 (cid:2) 109 n (cid:3) m2 (cid:8) C2 (cid:5) (cid:6) (cid:9) (cid:7) (5 (cid:2) 10 (cid:1)6 c)(5 (cid:2) 10 (cid:1)6 c) Fx = f31x + f32x = 11 n cos 45 (cid:1) 9 n = (cid:1)1. 1 n.

Related Questions

Coulomb's law for the magnitude of the force F between twoparticles with charges Q and Q' separated by a distance, d is |F| =K *|QQ'|/d2 where K=1/4peo = 8.854*10^-12 nC is the permittivity offree space.

Consider two point charges located on the x axis: one charge, q1 =-19.5nC , is located at x1= -1.680m ; the second charge, q2=31.5nC, is at the origin (x=0.0000).

What is the net force exerted by these two charges on a thirdcharge q3 = 52.5nC placed between q3 and at x3= -1.245m ? Youranswer may be positive or negative, depending on the direction ofthe force.

**Please solve with a numerical answer. I've tried this severaltimes and this is my last attempt on mastering physics.

Coulomb's law for the magnitude of the force between two particleswith charges and separated by a distance is |F| = K |QQ'|/d^2 whereK = 1/4piEo, Eo = 8.854 x 10^-12 C^2/Nxm^2. is the permittivity offree space.

Consider two point charges located on the x axis: one charge, q1 =-11.5nC , is located at x1 = -1.715 m; the second charge, q2 =34.5nC , is at the origin x = 0.00000.

What is the net force exerted by these two charges on a thirdcharge q3 = 49.5nC placed between q1 and q2 at x3 = -1.240m ?

Your answer may be positive or negative, depending on the directionof the force.

A cyclotron accelerates two protons directly toward each other,each with a speed of 1050 km/s, measured relative to the earth.Find the maximum electric force that these protons will exert oneach other.

This is all the information I was given, and this is how I tried tosolve. Can someone please work the problem? I'm out of time, andcompletely frazzled. All of my calculations have been wrong.

V = 1050 km/s

Permittivity of free space (e0) = 8.85*10-12

Mproton= 1.67*10-27

Charge of electron (e) = 1.602*10-19

1. k = 1/4*pi*e0 = 1.3 * 1011

2. r = ke2/mv2 = 5.84 * 1021

3. Fmax = ke2/r2 =?

PCS 211 Study Guide - Final Guide: Test Particle, Electric Field, Loa

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Physics: Principles with Applications

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