AEM 2021 Lecture Notes - Lecture 17: Rigid Body
17 May 2017
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Solution procedure (optional) do statics (fbd, 3 equation equilibrium, solve) of entire frame to get reactions. Dismember the frame and do statics for each member individually, get 3 equations for each. Frame- rigid (as a whole), attached to supports. At each connection, each member exerts a connection force on the other. A two force member (body) is a member of forces only at 2 points for equilibrium, forces at ends need to be equal and opposite, and loas must be ab. Can be smart to do statics on a subset of all members, then connection forces are internal, so they don"t have to be included. Find the forces on abc at b and c. ignore weights bd two force member gives direction (loa) of force (on abc) at b. abc is a multi force member. Note that this is not rigid without supports. Be has 2 forces, others have multiple forces. In homework, make sure dimensions are in fbd!
