ENGG 2230 Lecture : Ch 9 Solutions.doc
9 Apr 2013
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Chapter 9 compressible flow p1 = 140 kpa, t1 = 9. 1 an ideal gas flows adiabatically through a duct. Farther downstream, p2 = 30 kpa and t2 = 207(cid:176) c. calculate v2 in m/s and s2 - K) if the gas is (a) air, k = 1. 4, and (b) argon, k = 1. 67. s1 in j/(kg (cid:215) Solution: steady-flow energy equation (9. 23) is used to compute the downstream velocity: (a) for air, take. K, and cp = 1005 j/kg (cid:215) k. the adiabatic k = 1. 40, r = 287 j/kg (cid:215) c t p. 1 c ln(t /t ) r ln(p /p ) 1005ln p. 140 (b) for argon, take k = 1. 67, r = 208 j/kg (cid:215) Use two approaches: (a) an ideal gas from table a. 4; and (b) real steam from ees or the steam tables [15]. (cid:230) (cid:246) (cid:230) (cid:246) (cid:231) (cid:231) (cid:230) (cid:246) (cid:230) (cid:246) (cid:231) (cid:231)
