IAT 267 Lecture Notes - Lecture 3: Sulfide, Surface Charge, Electric Dipole Moment

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goldgerbil543

18 Aug 2013

School

Simon Fraser University

Department

Interactive Arts & Tech

Course

IAT 267

Professor

Helmine Serban

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Document Summary

There is only one path for electrons to flow. In any given circuit, the total voltage around the path of the circuit is zero. Or ir (e) = ir1 + ir2 + ir3. > r (e) = r1 + r2 + r3 (smaller current value) All components are connected between the same set of electrically common points. Points 1, 2, 3, 4 are all electrically common; so are 8, 7, 6, 5. All resistors as well as the battery are connected between these two sets of points. The amount of current going into any point in a circuit is the same as the amount coming out of that point. The three currents add up to the total current flowing out from point 2. Therefore, i = ir1 + ir2 + 1r3. Or v/r (e) = v/r1 + v/r2 + v/r3. > 1/r (e) = 1/r1 + 1/r2 + 1/r3.

Related Questions

I have some questions about direct current circuitquestions

1. Three resistors connected in parallel have individual values of67.0, 6.0, and 10.0 ohms, repectively. If this combination isconnected in series with a 12.0V battery and a 2.0ohm resisotr.what is the current in the 10ohm resistor (in A)? (I got 1.15A butthe answer is 0.77A I coudlnt' figure out that why the current is0.77A)

2. Four resistors, R1,R2,R3, and R4, are arrayed as follows in awheatstone bridge circuit between four junction points, a,b,c andd: R1 is between points a and b; R2 is between b and c; R3 isbetween a and d; R4 is between c and d. A galvanometer and switchare connected in series between b and d. This system is connectedin series to a battery at points a and c. When R3=4 ohms and theratio R2/R4=3, the galvanometer reads zero current with the switchclosed. what is thevalue of R1 (in ohms) (the answer is 12.0A)

and if under the condition of zero galvanometer current, withswitch closed, the potenial difference across R4 is 3V, then whatis the voltage across R2(in V)? (answer is 3.0V)