BIOB10Y3 Lecture Notes - Eukaryotic Initiation Factor, Kozak Consensus Sequence, Start Codon

120 views3 pages

erincheetah56

27 Sep 2012

School

Department

Course

Professor

For unlimited access to Class Notes, a Class+ subscription is required.

Document Summary

Mrnas transcribed from genese by rna poly ii. Exported to cytosol spliced, capped and polyadenylated. 2 subunits (large and small: large = 3 rrnas + proteins, small = 1 rrna + proteins. **imp for exam know difference b/w prokaryotic and eukaryotic subunits ** ribosomes are molecular machines require energy from gtp hydrolysis the ribosomal rnas are key components to their function. Help select the trnas, bind protein factors etc. the crystal structure of the ribosome (prokaryotic) helps us understand how this machine works. A long tunnel runs through the core of the large subunit (50s) and the newly synthesized protein comes through there protected. *we put all 3 types of rna together for translation: trnas (charged with aa) rrnas (ribosomes) Step 1 the small ribosomal subunit binds to the aug (start) codon. In prokaryotes, the correct aug codon is chosen by the presence of an upstream sequence: the shine-

Related Questions

Put the following list of events in the correct order following the steps required for eukaryotic gene expression: i. The ribosome shifts by one codon ii. A methionine-charged tRNA binds to the first AUG codon from the 5â end of the mRNA iii. An amino acid charged tRNA with the correct matching anticodon binds to the A-site iv. The amino acid from the tRNA in the P-site binds to the amino acid of the tRNA in the A-site v. The large ribosomal subunit binds vi. The small ribosomal subunit binds to a recognition sequence on the mRNA

violetbeetle442

Gene expression is a multi-step process. Place these events in the correct order.

Question 13 options:

charged tRNA molecules read the next codon, entering the A site of the ribosome.

Translocation of the mRNA to the cytoplasm.

Recruitment of RNA polymerase.

tRNA(Met) binds to the start codon AUG in the P site of the ribosome.

Assembly of small and large ribosome subunits on the mRNA.

Processing of the primary RNA molecule.

Release factors recognize the stop codon, signaling the release of the protein, mRNA and ribosome subunits.

Synthesis of primary RNA molecule, a direct copy of the DNA template.

Recognition of the mRNA by the small ribosome subunit .

Peptidyl transferase, transfers the amino acid of the incoming tRNA to the growing peptide chain.

Binding of transcription factors to the promoter.

blacklion206

Protein synthesis takes place much more slowly in eukaryotes than in prokaryotes. Which of the following is a reason that this is true?

Eukaryotic mRNA needs more processing than prokaryotic mRNA.

The formation of a peptide bond in prokaryotic ribosomes occurs nearly twice as fast as in eukaryotic ribosomes.

More time is needed for charged tRNAs to diffuse across the eukaryotic cell as compared to the prokaryotic cell.

Prokaryotes have higher concentrations of charged tRNAs than eukaryotes do.

brownhare189

BIOB10Y3 Lecture Notes - Eukaryotic Initiation Factor, Kozak Consensus Sequence, Start Codon

Document Summary

Get access

Related Documents

BIOB10H3 Lecture Notes - Lecture 18: Prokaryotic Small Ribosomal Subunit, Stop Codon, Eukaryotic Initiation Factor

PCB-3063 Study Guide - Final Guide: Fibroblast Growth Factor Receptor 2, Community Access Program, Polymerase Chain Reaction

BIOL 200 Lecture Notes - Lecture 6: Oogenesis, Base Pair, Eukaryotic Initiation Factor 3

Related Questions