PHYS 101 Study Guide - Joule, Itil, Trade Union Confederation Of The Americas

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goldhedgehog288

11 Oct 2012

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PHYS 101 Full Course Notes

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1 f d o d , f:2"0 cm d o : 2 . 2. 0 2. t di d i : 4 2 c m. The lens is 42 cm from the wall. 3 marks the student chose an appropriate procedure, but made minor errors in applying it or made an error in units. 2 marks the student chose an appropriate procedure, but made major erors in applying it. 0 marks the student showed no work (even if the answer is correct) or chose an inappropriate procedure; the answer is missing or incorrect, or it is correct purely by chance. ics 554-534. To reflect all ofthe light from the surface, the angle of incidence at point p, /. a, must be equal to or greater than the critical angle. Find the critical angle: lll : lloil: 1. 56. 5 6 x s i n a : 1 . 0 0 x s i n 9 0 t .

Related Questions

The figure is an edge-on view of a 14 cm diameter circular loop rotating in a uniform 3.8×10^-2 T magnetic field. I solved part a by using

φ= B A cos θ = Bπr² cosθ = (3.8 x 10^-2) π (.07)2cos (0 degrees)= 5.8 x 10^-4 Wb and got correct answer,

but having trouble finding the right answer for part B. I used the same equation for part B and used cos (30)= got the wrong answer. Is there another equation for finding the answer with the other angles?

Part A What is the magnetic flux through the loop when is 0 degrees?

Express your answer to two significant figures and include the appropriate units.
=5.8×10⁻⁴ Wb
Correct

Part B What is the magnetic flux through the loop when is 30 degrees?
Express your answer to two significant figures and include the appropriate units.
=

Part C
What is the magnetic flux through the loop when is 60 degrees?
Express your answer to two significant figures and include the appropriate units.
=

Part D What is the magnetic flux through the loop when is 90 degrees?
Express your answer to two significant figures and include the appropriate units