Mathematics 0110A/B Midterm: Midterm 2 Nov 9th 2009_sol.pdf

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[ 1 mark ] find f (2) where f (x) = = 2x 1, so f (x) = 2( x 2) = 2x 2 and f (x) = 2( 2x 3) = 4x 3 = [ 1 mark ] find f (1) where f (x) = x. Solution: f (x) = x = x1/2, so f (x) = (cid:0) 1. [ 1 mark ] find f (0) where f (x) = (1 x)4. And now we need the general power rule one more time: f (x) = 4[3(1 x)2( 1)] = 12(1 x)2 f (x) = 12[2(1 x)1( 1)] = 24(1 x) Therefore f (0) = 24(1 0) = 24(1) = 24. [ 1 mark ] find f (x) where f (x) = (x2 + 1)3. E: 6(x2 + 1)(x2 + 4x + 1) Solution: again we need the general power rule.

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