STAB22H3 Lecture 15: STAB22-LEC15-(15,16).docx
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STAB22H3 Full Course Notes
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Law and business school example (changed to something easier) Changed qn to one applicant, not two. Hint: if the question was talking about two randomly chosen applicants, then i think you would do: P(both accepted or both male or both) = P(both male) + p(both accepted) - p((male and accepted) and (male and accepted)) P(m or a or both) = p(a) + p(m) - p(a and m) => almost a cerainty that person you choose is either male or accepted. Note that we took into account: all males, and all accepted applicants. So, for this probability to fail, the probability of randomly picking out a rejected female will succeed. P(rejected and female) = 20/800, which is the same thing as 1 - (780/800). Only way is by getting female person who is rejected. Using complement rule can simplify your calculations.
