hassan_rizvi96

Calculate K at 298 K for the following reactions. Delta Gf kj/mol =

NOg...... 86.60

NO2g........... 51

O2.....0

Part A : NO(g) + 1/2 O2(g)......>> NO2(g)

Part B) Use the equilibrium constant ( K= 3.89 x 10^-34 at 298K ) to calculate Delta G (in kJ) at 298 for the following reaction:

2HCL (g)....> H2 (g) + CL2 (g)

answer delta G in kJ and in scientific notation please........

2HCL (g)....> H2 (g) + CL2 (g)