1
answer
218
views
90b
Problem

For access to Textbook Solutions, a Class+ or Grade+ subscription is required.

Textbook Expert
Textbook ExpertVerified Tutor
6 Nov 2021

Background and context

To Determine:

 

The acceleration of the system.

 

Solution:

 

Acceleration =0.88 m/s2.

 

Explanation:

Mass of the block,   

Mass of the bucket,   

Coefficient of static friction between the table and block is 0.45.

Coefficient of kinetic friction between the table and block is 0.32.

 

Formula used:

From Newton’s second law of motion:

  

Where, m is the mass and a is the acceleration.

 

Unlock all Textbook Solutions

Already have an account? Log in
Start filling in the gaps now
Log in