13 Nov 2021
Problem 57c
Page 375
Section: Cumulative Problems
Chapter 9: Chemical Bonding I:The Lewis Model
Textbook ExpertVerified Tutor
13 Nov 2021
Given information
The given a structural formula is 
.
Step-by-step explanation
Step 1.
To draw the Lewis structure at first, we could start writing the bond structure of Propanone. Since Carbon and Oxygen are more electronegative they will be considered as the central atoms.
Now, we need to calculate the total number of valence electrons present in the structure by adding all the valance electrons of each atom i.e
Total no. of valance electrons = 3 
No. of valance electrons in Carbon 
6 No. of valance electrons in Hydrogen valence electron of Oxygen
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Principles of Chemistry Molecular Approach
3rd Edition, 2014
Tro
ISBN: 9780321971944
Solutions
Chapter
Section
- Problem 43a
- Problem 43c
- Problem 43d
- Problem 44a
- Problem 44b
- Problem 44c
- Problem 44d
- Problem 45a
- Problem 45b
- Problem 45c
- Problem 45d
- Problem 46a
- Problem 46b
- Problem 46c
- Problem 46d
- Problem 47a
- Problem 47b
- Problem 47c
- Problem 47d
- Problem 48
- Problem 49
- Problem 50
- Problem 51
- Problem 52
- Problem 53
- Problem 54
- Problem 55
- Problem 56
- Problem 57a
- Problem 57b
- Problem 57c
- Problem 57d
- Problem 57e
- Problem 58a
- Problem 58b
- Problem 58c
- Problem 58d
- Problem 58e
- Problem 59
- Problem 60
- Problem 61
- Problem 62
- Problem 63
- Problem 64
- Problem 65a
- Problem 65b
- Problem 65c
- Problem 66
- Problem 67
- Problem 68
- Problem 69
- Problem 70