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Problem

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Textbook Expert
Textbook ExpertVerified Tutor
15 Nov 2021

Given information

the “Lap time” data for Lap 4=129; the sample size(n)=20; the degree of freedom (df)=20-1=19;

Step-by-step explanation

Step 1.

The sample mean for 132,129,127,125,132,129,131,130,128,132,131,130,128,131,129,128,131,130,129,128;

=(132+129+127+125+132+129+131+130+128+132+131+130+128+131+129+128+131+130+129+128)/20=129.5

The sample standard deviation(s);

(s)= (s)=2.124;

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